Base | Representation |
---|---|
bin | 1011111000101011101100… |
… | …1100000000100110011110 |
3 | 1201021022220102111121112120 |
4 | 2332022323030000212132 |
5 | 3203103121314031024 |
6 | 43443315422243410 |
7 | 2516106621462033 |
oct | 276127314004636 |
9 | 51238812447476 |
10 | 13068431002014 |
11 | 4189321675413 |
12 | 15708bb126566 |
13 | 73a46a03309b |
14 | 3327304d738a |
15 | 179e1716e479 |
hex | be2bb30099e |
13068431002014 has 16 divisors (see below), whose sum is σ = 26140155139728. Its totient is φ = 4355594811392.
The previous prime is 13068431002013. The next prime is 13068431002043. The reversal of 13068431002014 is 41020013486031.
13068431002014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13068431002013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 137162397 + ... + 137257640.
It is an arithmetic number, because the mean of its divisors is an integer number (1633759696233).
Almost surely, 213068431002014 is an apocalyptic number.
13068431002014 is an abundant number, since it is smaller than the sum of its proper divisors (13071724137714).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13068431002014 is a wasteful number, since it uses less digits than its factorization.
13068431002014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 274427979.
The product of its (nonzero) digits is 13824, while the sum is 33.
Adding to 13068431002014 its reverse (41020013486031), we get a palindrome (54088444488045).
The spelling of 13068431002014 in words is "thirteen trillion, sixty-eight billion, four hundred thirty-one million, two thousand, fourteen".
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