Base | Representation |
---|---|
bin | 111100110111010000… |
… | …0111010101001101011 |
3 | 110111100221000112101222 |
4 | 1321232200322221223 |
5 | 4120140001011413 |
6 | 140013313532255 |
7 | 12304642241345 |
oct | 1715640725153 |
9 | 414327015358 |
10 | 130703141483 |
11 | 504815747a2 |
12 | 213b827408b |
13 | c42c773a95 |
14 | 647ca20295 |
15 | 35ee956b08 |
hex | 1e6e83aa6b |
130703141483 has 2 divisors, whose sum is σ = 130703141484. Its totient is φ = 130703141482.
The previous prime is 130703141461. The next prime is 130703141531. The reversal of 130703141483 is 384141307031.
It is a weak prime.
It is an emirp because it is prime and its reverse (384141307031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130703141483 - 28 = 130703141227 is a prime.
It is a super-2 number, since 2×1307031414832 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (130703141423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65351570741 + 65351570742.
It is an arithmetic number, because the mean of its divisors is an integer number (65351570742).
Almost surely, 2130703141483 is an apocalyptic number.
130703141483 is a deficient number, since it is larger than the sum of its proper divisors (1).
130703141483 is an equidigital number, since it uses as much as digits as its factorization.
130703141483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 130703141483 in words is "one hundred thirty billion, seven hundred three million, one hundred forty-one thousand, four hundred eighty-three".
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