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1307064830657 is a prime number
BaseRepresentation
bin10011000001010011001…
…000101000101011000001
311121221202121002000221212
4103001103020220223001
5132403332044040112
62440242435255505
7163301166514325
oct23012310505301
94557677060855
101307064830657
11464361027013
1219139944a595
139634297c001
144739597d985
1523eee298522
hex13053228ac1

1307064830657 has 2 divisors, whose sum is σ = 1307064830658. Its totient is φ = 1307064830656.

The previous prime is 1307064830593. The next prime is 1307064830683. The reversal of 1307064830657 is 7560384607031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1306611311041 + 453519616 = 1143071^2 + 21296^2 .

It is an emirp because it is prime and its reverse (7560384607031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1307064830657 - 26 = 1307064830593 is a prime.

It is not a weakly prime, because it can be changed into another prime (1307064130657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653532415328 + 653532415329.

It is an arithmetic number, because the mean of its divisors is an integer number (653532415329).

Almost surely, 21307064830657 is an apocalyptic number.

It is an amenable number.

1307064830657 is a deficient number, since it is larger than the sum of its proper divisors (1).

1307064830657 is an equidigital number, since it uses as much as digits as its factorization.

1307064830657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 1307064830657 in words is "one trillion, three hundred seven billion, sixty-four million, eight hundred thirty thousand, six hundred fifty-seven".