Base | Representation |
---|---|
bin | 11101101110100010010010… |
… | …110001000101111111000011 |
3 | 122010220202001200100000122211 |
4 | 131232202102301011333003 |
5 | 114114031103302131342 |
6 | 1142021413034442551 |
7 | 36352513320631462 |
oct | 3556422261057703 |
9 | 563822050300584 |
10 | 130741266833347 |
11 | 38727072789575 |
12 | 127b6649893457 |
13 | 57c4b053991c1 |
14 | 243dca7dda9d9 |
15 | 101ad31475c17 |
hex | 76e892c45fc3 |
130741266833347 has 2 divisors, whose sum is σ = 130741266833348. Its totient is φ = 130741266833346.
The previous prime is 130741266833297. The next prime is 130741266833389. The reversal of 130741266833347 is 743338662147031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130741266833347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130741266833291 and 130741266833300.
It is not a weakly prime, because it can be changed into another prime (130741266833647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65370633416673 + 65370633416674.
It is an arithmetic number, because the mean of its divisors is an integer number (65370633416674).
Almost surely, 2130741266833347 is an apocalyptic number.
130741266833347 is a deficient number, since it is larger than the sum of its proper divisors (1).
130741266833347 is an equidigital number, since it uses as much as digits as its factorization.
130741266833347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36578304, while the sum is 58.
The spelling of 130741266833347 in words is "one hundred thirty trillion, seven hundred forty-one billion, two hundred sixty-six million, eight hundred thirty-three thousand, three hundred forty-seven".
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