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130783253398657 is a prime number
BaseRepresentation
bin11101101111001001011001…
…010111001000010010000001
3122011001202102210110112110021
4131233021121113020102001
5114120223100332224112
61142052555220333441
736355530636561046
oct3557113127102201
9564052383415407
10130783253398657
1138742959038522
1212802806b44281
1357c8a66ba0aa2
142441d2c3671cd
15101be8c569907
hex76f2595c8481

130783253398657 has 2 divisors, whose sum is σ = 130783253398658. Its totient is φ = 130783253398656.

The previous prime is 130783253398583. The next prime is 130783253398663. The reversal of 130783253398657 is 756893352387031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98331101769616 + 32452151629041 = 9916204^2 + 5696679^2 .

It is an emirp because it is prime and its reverse (756893352387031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130783253398657 - 235 = 130748893660289 is a prime.

It is not a weakly prime, because it can be changed into another prime (130783253398667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65391626699328 + 65391626699329.

It is an arithmetic number, because the mean of its divisors is an integer number (65391626699329).

Almost surely, 2130783253398657 is an apocalyptic number.

It is an amenable number.

130783253398657 is a deficient number, since it is larger than the sum of its proper divisors (1).

130783253398657 is an equidigital number, since it uses as much as digits as its factorization.

130783253398657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 685843200, while the sum is 70.

The spelling of 130783253398657 in words is "one hundred thirty trillion, seven hundred eighty-three billion, two hundred fifty-three million, three hundred ninety-eight thousand, six hundred fifty-seven".