Base | Representation |
---|---|
bin | 1011111001010111010100… |
… | …0110110000111101101011 |
3 | 1201022110010110021122021122 |
4 | 2332111311012300331223 |
5 | 3203301111332432021 |
6 | 43452533341325455 |
7 | 2520003031410662 |
oct | 276256506607553 |
9 | 51273113248248 |
10 | 13080140124011 |
11 | 4193290113044 |
12 | 157302856688b |
13 | 73b5b4b41b3c |
14 | 333121637dd9 |
15 | 17a3a00d3bab |
hex | be5751b0f6b |
13080140124011 has 2 divisors, whose sum is σ = 13080140124012. Its totient is φ = 13080140124010.
The previous prime is 13080140123971. The next prime is 13080140124113. The reversal of 13080140124011 is 11042104108031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13080140124011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13080140124211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6540070062005 + 6540070062006.
It is an arithmetic number, because the mean of its divisors is an integer number (6540070062006).
Almost surely, 213080140124011 is an apocalyptic number.
13080140124011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13080140124011 is an equidigital number, since it uses as much as digits as its factorization.
13080140124011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 26.
The spelling of 13080140124011 in words is "thirteen trillion, eighty billion, one hundred forty million, one hundred twenty-four thousand, eleven".
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