Base | Representation |
---|---|
bin | 10011000010100100010… |
… | …101000011010110100001 |
3 | 11122002021112022110002201 |
4 | 103002210111003112201 |
5 | 132414124310241121 |
6 | 2441025540213201 |
7 | 163350020223523 |
oct | 23024425032641 |
9 | 4562245273081 |
10 | 1308427040161 |
11 | 46499aa5419a |
12 | 1916b969a201 |
13 | 964cbc58837 |
14 | 47484855a13 |
15 | 2407db75e91 |
hex | 130a45435a1 |
1308427040161 has 2 divisors, whose sum is σ = 1308427040162. Its totient is φ = 1308427040160.
The previous prime is 1308427040111. The next prime is 1308427040191. The reversal of 1308427040161 is 1610407248031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1304291907136 + 4135133025 = 1142056^2 + 64305^2 .
It is a cyclic number.
It is not a de Polignac number, because 1308427040161 - 27 = 1308427040033 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1308427040161.
It is not a weakly prime, because it can be changed into another prime (1308427040101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654213520080 + 654213520081.
It is an arithmetic number, because the mean of its divisors is an integer number (654213520081).
Almost surely, 21308427040161 is an apocalyptic number.
It is an amenable number.
1308427040161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1308427040161 is an equidigital number, since it uses as much as digits as its factorization.
1308427040161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 37.
The spelling of 1308427040161 in words is "one trillion, three hundred eight billion, four hundred twenty-seven million, forty thousand, one hundred sixty-one".
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