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130879376321 is a prime number
BaseRepresentation
bin111100111100100000…
…1001100101111000001
3110111211012122012011012
41321321001030233001
54121020110020241
6140043011130305
712312212225501
oct1717101145701
9414735565135
10130879376321
1150561aa5621
12214472a3995
13c45a129c55
1464981b7a01
1536101696eb
hex1e7904cbc1

130879376321 has 2 divisors, whose sum is σ = 130879376322. Its totient is φ = 130879376320.

The previous prime is 130879376311. The next prime is 130879376413. The reversal of 130879376321 is 123673978031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77025676225 + 53853700096 = 277535^2 + 232064^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130879376321 is a prime.

It is a super-2 number, since 2×1308793763212 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130879376321.

It is not a weakly prime, because it can be changed into another prime (130879376311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65439688160 + 65439688161.

It is an arithmetic number, because the mean of its divisors is an integer number (65439688161).

Almost surely, 2130879376321 is an apocalyptic number.

It is an amenable number.

130879376321 is a deficient number, since it is larger than the sum of its proper divisors (1).

130879376321 is an equidigital number, since it uses as much as digits as its factorization.

130879376321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1143072, while the sum is 50.

The spelling of 130879376321 in words is "one hundred thirty billion, eight hundred seventy-nine million, three hundred seventy-six thousand, three hundred twenty-one".