Base | Representation |
---|---|
bin | 111100111100100010… |
… | …1001111100101100101 |
3 | 110111211021122001120002 |
4 | 1321321011033211211 |
5 | 4121020342432311 |
6 | 140043045551045 |
7 | 12312224232566 |
oct | 1717105174545 |
9 | 414737561502 |
10 | 130880436581 |
11 | 5056265a174 |
12 | 21447715485 |
13 | c45a40b71b |
14 | 64983b216d |
15 | 36102c893b |
hex | 1e7914f965 |
130880436581 has 4 divisors (see below), whose sum is σ = 131237059392. Its totient is φ = 130523813772.
The previous prime is 130880436487. The next prime is 130880436619. The reversal of 130880436581 is 185634088031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 130880436581 - 218 = 130880174437 is a prime.
It is a super-2 number, since 2×1308804365812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130880430581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178310855 + ... + 178311588.
It is an arithmetic number, because the mean of its divisors is an integer number (32809264848).
Almost surely, 2130880436581 is an apocalyptic number.
It is an amenable number.
130880436581 is a deficient number, since it is larger than the sum of its proper divisors (356622811).
130880436581 is an equidigital number, since it uses as much as digits as its factorization.
130880436581 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 356622810.
The product of its (nonzero) digits is 552960, while the sum is 47.
The spelling of 130880436581 in words is "one hundred thirty billion, eight hundred eighty million, four hundred thirty-six thousand, five hundred eighty-one".
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