Base | Representation |
---|---|
bin | 1011111001110110011001… |
… | …0101000011110101101101 |
3 | 1201100020122211021100110201 |
4 | 2332131212111003311231 |
5 | 3203420202412211233 |
6 | 43500433220033501 |
7 | 2520416534424511 |
oct | 276354625036555 |
9 | 51306584240421 |
10 | 13088482147693 |
11 | 4196880a57997 |
12 | 1574776232891 |
13 | 73c3141a7724 |
14 | 3336b34d4141 |
15 | 17a6dc63e77d |
hex | be766543d6d |
13088482147693 has 4 divisors (see below), whose sum is σ = 13100523070720. Its totient is φ = 13076441224668.
The previous prime is 13088482147691. The next prime is 13088482147703. The reversal of 13088482147693 is 39674128488031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13088482147693 - 21 = 13088482147691 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13088482147691) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6020459883 + ... + 6020462056.
It is an arithmetic number, because the mean of its divisors is an integer number (3275130767680).
Almost surely, 213088482147693 is an apocalyptic number.
It is an amenable number.
13088482147693 is a deficient number, since it is larger than the sum of its proper divisors (12040923027).
13088482147693 is a wasteful number, since it uses less digits than its factorization.
13088482147693 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12040923026.
The product of its (nonzero) digits is 55738368, while the sum is 64.
The spelling of 13088482147693 in words is "thirteen trillion, eighty-eight billion, four hundred eighty-two million, one hundred forty-seven thousand, six hundred ninety-three".
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