Base | Representation |
---|---|
bin | 10011000011000111010… |
… | …100100100100000000001 |
3 | 11122010210110000000020101 |
4 | 103003013110210200001 |
5 | 132421330103210403 |
6 | 2441204111242401 |
7 | 163400406255106 |
oct | 23030724444001 |
9 | 4563713000211 |
10 | 1309014116353 |
11 | 465171385229 |
12 | 191842219401 |
13 | 9659377aab8 |
14 | 474dc7d6aad |
15 | 240b548e71d |
hex | 130c7524801 |
1309014116353 has 2 divisors, whose sum is σ = 1309014116354. Its totient is φ = 1309014116352.
The previous prime is 1309014116323. The next prime is 1309014116363. The reversal of 1309014116353 is 3536114109031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1307196628929 + 1817487424 = 1143327^2 + 42632^2 .
It is a cyclic number.
It is not a de Polignac number, because 1309014116353 - 217 = 1309013985281 is a prime.
It is a super-2 number, since 2×13090141163532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1309014116303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654507058176 + 654507058177.
It is an arithmetic number, because the mean of its divisors is an integer number (654507058177).
Almost surely, 21309014116353 is an apocalyptic number.
It is an amenable number.
1309014116353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1309014116353 is an equidigital number, since it uses as much as digits as its factorization.
1309014116353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 37.
The spelling of 1309014116353 in words is "one trillion, three hundred nine billion, fourteen million, one hundred sixteen thousand, three hundred fifty-three".
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