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130921217297833 is a prime number
BaseRepresentation
bin11101110001001001111000…
…101001101000110110101001
3122011112221112201212202221211
4131301021320221220312221
5114130003123112012313
61142240213225433121
736401513545430254
oct3561117051506651
9564487481782854
10130921217297833
1138796416067a06
12128254aa93b7a1
135808a829888a1
1424488993c009b
151020864646e3d
hex771278a68da9

130921217297833 has 2 divisors, whose sum is σ = 130921217297834. Its totient is φ = 130921217297832.

The previous prime is 130921217297737. The next prime is 130921217297863. The reversal of 130921217297833 is 338792712129031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127896828485904 + 3024388811929 = 11309148^2 + 1739077^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130921217297833 is a prime.

It is not a weakly prime, because it can be changed into another prime (130921217297863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65460608648916 + 65460608648917.

It is an arithmetic number, because the mean of its divisors is an integer number (65460608648917).

Almost surely, 2130921217297833 is an apocalyptic number.

It is an amenable number.

130921217297833 is a deficient number, since it is larger than the sum of its proper divisors (1).

130921217297833 is an equidigital number, since it uses as much as digits as its factorization.

130921217297833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6858432, while the sum is 58.

The spelling of 130921217297833 in words is "one hundred thirty trillion, nine hundred twenty-one billion, two hundred seventeen million, two hundred ninety-seven thousand, eight hundred thirty-three".