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1309418114343 = 3436472704781
BaseRepresentation
bin10011000011011111011…
…001101100110100100111
311122011211121012020021220
4103003133121230310213
5132423142014124333
62441312142311423
7163413413220603
oct23033731546447
94564747166256
101309418114343
11465359430969
12191935588573
139662938c071
144753a31c503
15240dab928b3
hex130df66cd27

1309418114343 has 4 divisors (see below), whose sum is σ = 1745890819128. Its totient is φ = 872945409560.

The previous prime is 1309418114327. The next prime is 1309418114357. The reversal of 1309418114343 is 3434118149031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1309418114343 - 24 = 1309418114327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1309418114295 and 1309418114304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1309418114143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218236352388 + ... + 218236352393.

It is an arithmetic number, because the mean of its divisors is an integer number (436472704782).

Almost surely, 21309418114343 is an apocalyptic number.

1309418114343 is a deficient number, since it is larger than the sum of its proper divisors (436472704785).

1309418114343 is an equidigital number, since it uses as much as digits as its factorization.

1309418114343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 436472704784.

The product of its (nonzero) digits is 124416, while the sum is 42.

The spelling of 1309418114343 in words is "one trillion, three hundred nine billion, four hundred eighteen million, one hundred fourteen thousand, three hundred forty-three".

Divisors: 1 3 436472704781 1309418114343