Base | Representation |
---|---|
bin | 10011000011011111011… |
… | …001101100110001011111 |
3 | 11122011211121012020000111 |
4 | 103003133121230301133 |
5 | 132423142014123033 |
6 | 2441312142310451 |
7 | 163413413220166 |
oct | 23033731546137 |
9 | 4564747166014 |
10 | 1309418114143 |
11 | 4653594307a7 |
12 | 191935588427 |
13 | 9662938bc49 |
14 | 4753a31c3dd |
15 | 240dab927cd |
hex | 130df66cc5f |
1309418114143 has 2 divisors, whose sum is σ = 1309418114144. Its totient is φ = 1309418114142.
The previous prime is 1309418114141. The next prime is 1309418114149. The reversal of 1309418114143 is 3414118149031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1309418114143 - 21 = 1309418114141 is a prime.
Together with 1309418114141, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1309418114096 and 1309418114105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1309418114141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654709057071 + 654709057072.
It is an arithmetic number, because the mean of its divisors is an integer number (654709057072).
Almost surely, 21309418114143 is an apocalyptic number.
1309418114143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1309418114143 is an equidigital number, since it uses as much as digits as its factorization.
1309418114143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 40.
The spelling of 1309418114143 in words is "one trillion, three hundred nine billion, four hundred eighteen million, one hundred fourteen thousand, one hundred forty-three".
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