Base | Representation |
---|---|
bin | 10011000011101111010… |
… | …111100101010001010001 |
3 | 11122012112021020221220001 |
4 | 103003233113211101101 |
5 | 132424214103311302 |
6 | 2441354512050001 |
7 | 163423145162542 |
oct | 23035727452121 |
9 | 4565467227801 |
10 | 1309685994577 |
11 | 465486667294 |
12 | 1919ab233901 |
13 | 9666ca2208c |
14 | 47563b304c9 |
15 | 24104459787 |
hex | 130ef5e5451 |
1309685994577 has 2 divisors, whose sum is σ = 1309685994578. Its totient is φ = 1309685994576.
The previous prime is 1309685994569. The next prime is 1309685994583. The reversal of 1309685994577 is 7754995869031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1198479752001 + 111206242576 = 1094751^2 + 333476^2 .
It is a cyclic number.
It is not a de Polignac number, because 1309685994577 - 23 = 1309685994569 is a prime.
It is a super-2 number, since 2×13096859945772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1309685994587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654842997288 + 654842997289.
It is an arithmetic number, because the mean of its divisors is an integer number (654842997289).
Almost surely, 21309685994577 is an apocalyptic number.
It is an amenable number.
1309685994577 is a deficient number, since it is larger than the sum of its proper divisors (1).
1309685994577 is an equidigital number, since it uses as much as digits as its factorization.
1309685994577 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 514382400, while the sum is 73.
The spelling of 1309685994577 in words is "one trillion, three hundred nine billion, six hundred eighty-five million, nine hundred ninety-four thousand, five hundred seventy-seven".
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