Base | Representation |
---|---|
bin | 11101110001111101101000… |
… | …100010010001000110011011 |
3 | 122011202020222002201221202202 |
4 | 131301331220202101012123 |
5 | 114131410422031124143 |
6 | 1142321522555320415 |
7 | 36405521513413154 |
oct | 3561755042210633 |
9 | 564666862657682 |
10 | 130976781504923 |
11 | 38807a39669112 |
12 | 1283421715010b |
13 | 5811099430133 |
14 | 244b44aabc92b |
15 | 1022017740ab8 |
hex | 771f6889119b |
130976781504923 has 2 divisors, whose sum is σ = 130976781504924. Its totient is φ = 130976781504922.
The previous prime is 130976781504913. The next prime is 130976781504929. The reversal of 130976781504923 is 329405187679031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130976781504923 - 218 = 130976781242779 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130976781504923.
It is not a weakly prime, because it can be changed into another prime (130976781504929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65488390752461 + 65488390752462.
It is an arithmetic number, because the mean of its divisors is an integer number (65488390752462).
It is a 1-persistent number, because it is pandigital, but 2⋅130976781504923 = 261953563009846 is not.
Almost surely, 2130976781504923 is an apocalyptic number.
130976781504923 is a deficient number, since it is larger than the sum of its proper divisors (1).
130976781504923 is an equidigital number, since it uses as much as digits as its factorization.
130976781504923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68584320, while the sum is 65.
The spelling of 130976781504923 in words is "one hundred thirty trillion, nine hundred seventy-six billion, seven hundred eighty-one million, five hundred four thousand, nine hundred twenty-three".
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