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13100003001334 = 26550001500667
BaseRepresentation
bin1011111010100001010100…
…0001101000001111110110
31201101100101201210100120201
42332220111001220033312
53204112301232020314
643510020331551114
72521305200160214
oct276502501501766
951340351710521
1013100003001334
1141a07531a5837
121576a505bb49a
1374042bca8ca2
14334087627cb4
1517ab63cb5b74
hexbea150683f6

13100003001334 has 4 divisors (see below), whose sum is σ = 19650004502004. Its totient is φ = 6550001500666.

The previous prime is 13100003001329. The next prime is 13100003001347. The reversal of 13100003001334 is 43310030000131.

13100003001334 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×131000030013342 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275000750332 + ... + 3275000750335.

It is an arithmetic number, because the mean of its divisors is an integer number (4912501125501).

Almost surely, 213100003001334 is an apocalyptic number.

13100003001334 is a deficient number, since it is larger than the sum of its proper divisors (6550001500670).

13100003001334 is an equidigital number, since it uses as much as digits as its factorization.

13100003001334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6550001500669.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13100003001334 its reverse (43310030000131), we get a palindrome (56410033001465).

The spelling of 13100003001334 in words is "thirteen trillion, one hundred billion, three million, one thousand, three hundred thirty-four".

Divisors: 1 2 6550001500667 13100003001334