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13100003001444 = 2231091666916787
BaseRepresentation
bin1011111010100001010100…
…0001101000010001100100
31201101100101201210100201210
42332220111001220101210
53204112301232021234
643510020331551420
72521305200160432
oct276502501502144
951340351710653
1013100003001444
1141a07531a5927
121576a505bb570
1374042bca9058
14334087627d52
1517ab63cb5be9
hexbea15068464

13100003001444 has 12 divisors (see below), whose sum is σ = 30566673670064. Its totient is φ = 4366667667144.

The previous prime is 13100003001427. The next prime is 13100003001457. The reversal of 13100003001444 is 44410030000131.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×131000030014442 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13100003001444.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545833458382 + ... + 545833458405.

Almost surely, 213100003001444 is an apocalyptic number.

It is an amenable number.

13100003001444 is an abundant number, since it is smaller than the sum of its proper divisors (17466670668620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100003001444 is a wasteful number, since it uses less digits than its factorization.

13100003001444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1091666916794 (or 1091666916792 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13100003001444 its reverse (44410030000131), we get a palindrome (57510033001575).

The spelling of 13100003001444 in words is "thirteen trillion, one hundred billion, three million, one thousand, four hundred forty-four".

Divisors: 1 2 3 4 6 12 1091666916787 2183333833574 3275000750361 4366667667148 6550001500722 13100003001444