Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …010100100001000000000011 |
3 | 122011211110222101222211210201 |
4 | 131302103102110201000003 |
5 | 114132301030431341121 |
6 | 1142340330011310031 |
7 | 36410303615036464 |
oct | 3562232224410003 |
9 | 564743871884721 |
10 | 131000031121411 |
11 | 3881688a44a0a1 |
12 | 1283882544b317 |
13 | 581333312925a |
14 | 244c6147c6d6b |
15 | 102292890ae91 |
hex | 7724d2521003 |
131000031121411 has 2 divisors, whose sum is σ = 131000031121412. Its totient is φ = 131000031121410.
The previous prime is 131000031121361. The next prime is 131000031121517. The reversal of 131000031121411 is 114121130000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131000031121411 - 27 = 131000031121283 is a prime.
It is a super-2 number, since 2×1310000311214112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131000031128411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500015560705 + 65500015560706.
It is an arithmetic number, because the mean of its divisors is an integer number (65500015560706).
Almost surely, 2131000031121411 is an apocalyptic number.
131000031121411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000031121411 is an equidigital number, since it uses as much as digits as its factorization.
131000031121411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 131000031121411 its reverse (114121130000131), we get a palindrome (245121161121542).
The spelling of 131000031121411 in words is "one hundred thirty-one trillion, thirty-one million, one hundred twenty-one thousand, four hundred eleven".
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