131000041213214 has 4 divisors (see below), whose sum is σ = 196500061819824. Its totient is φ = 65500020606606.

The previous prime is 131000041213103. The next prime is 131000041213219. The reversal of 131000041213214 is 412312140000131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×131000041213214³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 131000041213214.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000041213219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750010303302 + ... + 32750010303305.

It is an arithmetic number, because the mean of its divisors is an integer number (49125015454956).

Almost surely, 2^{131000041213214} is an apocalyptic number.

131000041213214 is a deficient number, since it is larger than the sum of its proper divisors (65500020606610).

131000041213214 is an equidigital number, since it uses as much as digits as its factorization.

131000041213214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65500020606609.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131000041213214 its reverse (412312140000131), we get a palindrome (543312181213345).

The spelling of 131000041213214 in words is "one hundred thirty-one trillion, forty-one million, two hundred thirteen thousand, two hundred fourteen".