Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …111110000110110110010101 |
3 | 122011211111000011111202210221 |
4 | 131302103102332012312111 |
5 | 114132301041224234331 |
6 | 1142340331041114341 |
7 | 36410304106516450 |
oct | 3562232276066625 |
9 | 564744004452727 |
10 | 131000042024341 |
11 | 38816895616686 |
12 | 128388290289b1 |
13 | 5813335475aa9 |
14 | 244c616024497 |
15 | 1022929861711 |
hex | 7724d2f86d95 |
131000042024341 has 16 divisors (see below), whose sum is σ = 150679157827968. Its totient is φ = 111564447825600.
The previous prime is 131000042024281. The next prime is 131000042024381. The reversal of 131000042024341 is 143420240000131.
It is not a de Polignac number, because 131000042024341 - 217 = 131000041893269 is a prime.
It is a super-2 number, since 2×1310000420243412 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000042024381) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95803450 + ... + 97161211.
It is an arithmetic number, because the mean of its divisors is an integer number (9417447364248).
Almost surely, 2131000042024341 is an apocalyptic number.
It is an amenable number.
131000042024341 is a deficient number, since it is larger than the sum of its proper divisors (19679115803627).
131000042024341 is a wasteful number, since it uses less digits than its factorization.
131000042024341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 192965292.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 131000042024341 its reverse (143420240000131), we get a palindrome (274420282024472).
The spelling of 131000042024341 in words is "one hundred thirty-one trillion, forty-two million, twenty-four thousand, three hundred forty-one".
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