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131000100000000 = 2835871153107
BaseRepresentation
bin11101110010010011010110…
…011011010001000100000000
3122011211111011012121020110120
4131302103112123101010000
5114132301201100000000
61142340340511500240
736410305412352630
oct3562232633210400
9564744135536416
10131000100000000
1138816915314650
1212838844527680
13581334449450a
14244c61d9d66c0
15102292e9b46a0
hex7724d66d1100

131000100000000 has 2592 divisors, whose sum is σ = 558778213905408. Its totient is φ = 26457600000000.

The previous prime is 131000099999933. The next prime is 131000100000047. The reversal of 131000100000000 is 1000131.

It is a super-2 number, since 2×1310001000000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (6).

It is a super Niven number, because it is divisible the sum of any subset of its (nonzero) digits.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 1224299999947 + ... + 1224300000053.

It is an arithmetic number, because the mean of its divisors is an integer number (215578014624).

Almost surely, 2131000100000000 is an apocalyptic number.

131000100000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000100000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (279389106952704).

131000100000000 is an abundant number, since it is smaller than the sum of its proper divisors (427778113905408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000100000000 is an frugal number, since it uses more digits than its factorization.

131000100000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237 (or 188 counting only the distinct ones).

The product of its (nonzero) digits is 3, while the sum is 6.

Adding to 131000100000000 its reverse (1000131), we get a palindrome (131000101000131).

The spelling of 131000100000000 in words is "one hundred thirty-one trillion, one hundred million", and thus it is an aban number.