131000104020043 has 2 divisors, whose sum is σ = 131000104020044. Its totient is φ = 131000104020042.

The previous prime is 131000104019951. The next prime is 131000104020053. The reversal of 131000104020043 is 340020401000131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131000104020043 - 2⁹ = 131000104019531 is a prime.

It is a super-2 number, since 2×131000104020043² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131000104020043.

It is not a weakly prime, because it can be changed into another prime (131000104020053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500052010021 + 65500052010022.

It is an arithmetic number, because the mean of its divisors is an integer number (65500052010022).

Almost surely, 2^{131000104020043} is an apocalyptic number.

131000104020043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000104020043 is an equidigital number, since it uses as much as digits as its factorization.

131000104020043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 131000104020043 its reverse (340020401000131), we get a palindrome (471020505020174).

The spelling of 131000104020043 in words is "one hundred thirty-one trillion, one hundred four million, twenty thousand, forty-three".