Base | Representation |
---|---|
bin | 1011111010100001010110… |
… | …0000100010001101101011 |
3 | 1201101100102022000222002111 |
4 | 2332220111200202031223 |
5 | 3204112310320244313 |
6 | 43510021221343151 |
7 | 2521305326062402 |
oct | 276502540421553 |
9 | 51340368028074 |
10 | 13100011103083 |
11 | 41a07578297a3 |
12 | 1576a53267ab7 |
13 | 740430884818 |
14 | 334088736639 |
15 | 17ab6486643d |
hex | bea1582236b |
13100011103083 has 2 divisors, whose sum is σ = 13100011103084. Its totient is φ = 13100011103082.
The previous prime is 13100011103071. The next prime is 13100011103111. The reversal of 13100011103083 is 38030111000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100011103083 - 221 = 13100009005931 is a prime.
It is a super-2 number, since 2×131000111030832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13100011103183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550005551541 + 6550005551542.
It is an arithmetic number, because the mean of its divisors is an integer number (6550005551542).
Almost surely, 213100011103083 is an apocalyptic number.
13100011103083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100011103083 is an equidigital number, since it uses as much as digits as its factorization.
13100011103083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 22.
The spelling of 13100011103083 in words is "thirteen trillion, one hundred billion, eleven million, one hundred three thousand, eighty-three".
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