Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …010001000010001100001 |
3 | 11122020100020102211111210 |
4 | 103010002022020101201 |
5 | 132430340304010131 |
6 | 2441450052500333 |
7 | 163434023526132 |
oct | 23040212102141 |
9 | 4566306384453 |
10 | 1310001235041 |
11 | 4656286000a4 |
12 | 191a7891a6a9 |
13 | 966c0127ab5 |
14 | 4759394dc89 |
15 | 24121e79146 |
hex | 13102288461 |
1310001235041 has 32 divisors (see below), whose sum is σ = 1790595072000. Its totient is φ = 851517842240.
The previous prime is 1310001235033. The next prime is 1310001235057. The reversal of 1310001235041 is 1405321000131.
It is a cyclic number.
It is not a de Polignac number, because 1310001235041 - 23 = 1310001235033 is a prime.
It is a super-2 number, since 2×13100012350412 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1310001234999 and 1310001235017.
It is not an unprimeable number, because it can be changed into a prime (1310001235061) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40439671 + ... + 40472051.
It is an arithmetic number, because the mean of its divisors is an integer number (55956096000).
Almost surely, 21310001235041 is an apocalyptic number.
It is an amenable number.
1310001235041 is a deficient number, since it is larger than the sum of its proper divisors (480593836959).
1310001235041 is a wasteful number, since it uses less digits than its factorization.
1310001235041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33509.
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 1310001235041 its reverse (1405321000131), we get a palindrome (2715322235172).
The spelling of 1310001235041 in words is "one trillion, three hundred ten billion, one million, two hundred thirty-five thousand, forty-one".
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