Base | Representation |
---|---|
bin | 1011111010100001011000… |
… | …0100000100111011001101 |
3 | 1201101100102221120022220122 |
4 | 2332220112010010323031 |
5 | 3204112320211422201 |
6 | 43510022153154325 |
7 | 2521305501216323 |
oct | 276502604047315 |
9 | 51340387508818 |
10 | 13100020420301 |
11 | 41a0762012981 |
12 | 1576a563bb9a5 |
13 | 740432797679 |
14 | 334089a7dd13 |
15 | 17ab655a6e1b |
hex | bea16104ecd |
13100020420301 has 8 divisors (see below), whose sum is σ = 13142362508184. Its totient is φ = 13057684729920.
The previous prime is 13100020420243. The next prime is 13100020420327. The reversal of 13100020420301 is 10302402000131.
It can be written as a sum of positive squares in 4 ways, for example, as 1897437375625 + 11202583044676 = 1377475^2 + 3347026^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13100020420301 - 218 = 13100020158157 is a prime.
It is a super-3 number, since 3×131000204203013 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13100020420301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100020420351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2519711 + ... + 5705171.
It is an arithmetic number, because the mean of its divisors is an integer number (1642795313523).
Almost surely, 213100020420301 is an apocalyptic number.
It is an amenable number.
13100020420301 is a deficient number, since it is larger than the sum of its proper divisors (42342087883).
13100020420301 is a wasteful number, since it uses less digits than its factorization.
13100020420301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3198751.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 13100020420301 its reverse (10302402000131), we get a palindrome (23402422420432).
The spelling of 13100020420301 in words is "thirteen trillion, one hundred billion, twenty million, four hundred twenty thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •