Base | Representation |
---|---|
bin | 1011111010100001011000… |
… | …0100000100111011111111 |
3 | 1201101100102221120022222111 |
4 | 2332220112010010323333 |
5 | 3204112320211422401 |
6 | 43510022153154451 |
7 | 2521305501216424 |
oct | 276502604047377 |
9 | 51340387508874 |
10 | 13100020420351 |
11 | 41a0762012a17 |
12 | 1576a563bba27 |
13 | 7404327976b7 |
14 | 334089a7dd4b |
15 | 17ab655a6e51 |
hex | bea16104eff |
13100020420351 has 2 divisors, whose sum is σ = 13100020420352. Its totient is φ = 13100020420350.
The previous prime is 13100020420337. The next prime is 13100020420387. The reversal of 13100020420351 is 15302402000131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100020420351 - 243 = 4303927398143 is a prime.
It is a super-2 number, since 2×131000204203512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100020420391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550010210175 + 6550010210176.
It is an arithmetic number, because the mean of its divisors is an integer number (6550010210176).
Almost surely, 213100020420351 is an apocalyptic number.
13100020420351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100020420351 is an equidigital number, since it uses as much as digits as its factorization.
13100020420351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 13100020420351 its reverse (15302402000131), we get a palindrome (28402422420482).
The spelling of 13100020420351 in words is "thirteen trillion, one hundred billion, twenty million, four hundred twenty thousand, three hundred fifty-one".
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