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1310003011006 = 2655001505503
BaseRepresentation
bin10011000100000010010…
…000111001110110111110
311122020100100210001200021
4103010002100321312332
5132430341232323011
62441450154522354
7163434044603644
oct23040220716676
94566310701607
101310003011006
11465629603438
12191a794363ba
13966c05ca271
1447593c93194
15241221ca471
hex13102439dbe

1310003011006 has 4 divisors (see below), whose sum is σ = 1965004516512. Its totient is φ = 655001505502.

The previous prime is 1310003011003. The next prime is 1310003011013. The reversal of 1310003011006 is 6001103000131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13100030110062 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310003011003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327500752750 + ... + 327500752753.

It is an arithmetic number, because the mean of its divisors is an integer number (491251129128).

Almost surely, 21310003011006 is an apocalyptic number.

1310003011006 is a deficient number, since it is larger than the sum of its proper divisors (655001505506).

1310003011006 is an equidigital number, since it uses as much as digits as its factorization.

1310003011006 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655001505505.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1310003011006 its reverse (6001103000131), we get a palindrome (7311106011137).

The spelling of 1310003011006 in words is "one trillion, three hundred ten billion, three million, eleven thousand, six".

Divisors: 1 2 655001505503 1310003011006