Base | Representation |
---|---|
bin | 111101000000000111… |
… | …0011111011001101011 |
3 | 110112010122011210212001 |
4 | 1322000032133121223 |
5 | 4121242034114123 |
6 | 140103011031431 |
7 | 12315211121164 |
oct | 1720016373153 |
9 | 415118153761 |
10 | 131000301163 |
11 | 50614289206 |
12 | 2147b89b577 |
13 | c4791b8b04 |
14 | 64aa29476b |
15 | 361aaa40ad |
hex | 1e8039f66b |
131000301163 has 2 divisors, whose sum is σ = 131000301164. Its totient is φ = 131000301162.
The previous prime is 131000301119. The next prime is 131000301269. The reversal of 131000301163 is 361103000131.
It is a weak prime.
It is an emirp because it is prime and its reverse (361103000131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131000301163 - 225 = 130966746731 is a prime.
It is a super-2 number, since 2×1310003011632 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131000301163.
It is not a weakly prime, because it can be changed into another prime (131000301763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500150581 + 65500150582.
It is an arithmetic number, because the mean of its divisors is an integer number (65500150582).
Almost surely, 2131000301163 is an apocalyptic number.
131000301163 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000301163 is an equidigital number, since it uses as much as digits as its factorization.
131000301163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 131000301163 its reverse (361103000131), we get a palindrome (492103301294).
The spelling of 131000301163 in words is "one hundred thirty-one billion, three hundred one thousand, one hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •