13100030401433 has 2 divisors, whose sum is σ = 13100030401434. Its totient is φ = 13100030401432.

The previous prime is 13100030401331. The next prime is 13100030401463. The reversal of 13100030401433 is 33410403000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12847371368329 + 252659033104 = 3584323^2 + 502652^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100030401433 - 2¹⁸ = 13100030139289 is a prime.

It is a super-2 number, since 2×13100030401433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100030401399 and 13100030401408.

It is not a weakly prime, because it can be changed into another prime (13100030401463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550015200716 + 6550015200717.

It is an arithmetic number, because the mean of its divisors is an integer number (6550015200717).

Almost surely, 2^{13100030401433} is an apocalyptic number.

It is an amenable number.

13100030401433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100030401433 is an equidigital number, since it uses as much as digits as its factorization.

13100030401433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13100030401433 its reverse (33410403000131), we get a palindrome (46510433401564).

The spelling of 13100030401433 in words is "thirteen trillion, one hundred billion, thirty million, four hundred one thousand, four hundred thirty-three".