Base | Representation |
---|---|
bin | 1011111010100001011010… |
… | …1100010100010010010011 |
3 | 1201101100110200102020222102 |
4 | 2332220112230110102103 |
5 | 3204112330412001404 |
6 | 43510023211231015 |
7 | 2521305656662433 |
oct | 276502654242223 |
9 | 51340420366872 |
10 | 13100030968979 |
11 | 41a0767a68299 |
12 | 1576a59a4846b |
13 | 740434a1bba6 |
14 | 33408b2282c3 |
15 | 17ab6648c71e |
hex | bea16b14493 |
13100030968979 has 2 divisors, whose sum is σ = 13100030968980. Its totient is φ = 13100030968978.
The previous prime is 13100030968903. The next prime is 13100030969023. The reversal of 13100030968979 is 97986903000131.
It is a strong prime.
It is an emirp because it is prime and its reverse (97986903000131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13100030968979 - 224 = 13100014191763 is a prime.
It is a super-2 number, since 2×131000309689792 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13100030968879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550015484489 + 6550015484490.
It is an arithmetic number, because the mean of its divisors is an integer number (6550015484490).
Almost surely, 213100030968979 is an apocalyptic number.
13100030968979 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100030968979 is an equidigital number, since it uses as much as digits as its factorization.
13100030968979 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2204496, while the sum is 56.
The spelling of 13100030968979 in words is "thirteen trillion, one hundred billion, thirty million, nine hundred sixty-eight thousand, nine hundred seventy-nine".
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