Base | Representation |
---|---|
bin | 11101110010010011100011… |
… | …100110010110110100111011 |
3 | 122011211111201121110202120021 |
4 | 131302103203212112310323 |
5 | 114132302124134323003 |
6 | 1142340414444511311 |
7 | 36410314035046603 |
oct | 3562234346266473 |
9 | 564744647422507 |
10 | 131000321011003 |
11 | 38816a19048474 |
12 | 128388a654b537 |
13 | 581337b1c7162 |
14 | 244c6410c7c03 |
15 | 10229440be2bd |
hex | 7724e3996d3b |
131000321011003 has 2 divisors, whose sum is σ = 131000321011004. Its totient is φ = 131000321011002.
The previous prime is 131000321010989. The next prime is 131000321011057. The reversal of 131000321011003 is 300110123000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131000321011003 - 221 = 131000318913851 is a prime.
It is a super-2 number, since 2×1310003210110032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131000321012003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500160505501 + 65500160505502.
It is an arithmetic number, because the mean of its divisors is an integer number (65500160505502).
Almost surely, 2131000321011003 is an apocalyptic number.
131000321011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000321011003 is an equidigital number, since it uses as much as digits as its factorization.
131000321011003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131000321011003 its reverse (300110123000131), we get a palindrome (431110444011134).
The spelling of 131000321011003 in words is "one hundred thirty-one trillion, three hundred twenty-one million, eleven thousand, three".
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