Base | Representation |
---|---|
bin | 11101110010010011100100… |
… | …111011000011000000001011 |
3 | 122011211111210011020200200000 |
4 | 131302103210323003000023 |
5 | 114132302200330241133 |
6 | 1142340421000414043 |
7 | 36410314424543634 |
oct | 3562234473030013 |
9 | 564744704220600 |
10 | 131000343212043 |
11 | 38816a2a631438 |
12 | 128388b1a77323 |
13 | 581338299b376 |
14 | 244c64402688b |
15 | 1022946007413 |
hex | 7724e4ec300b |
131000343212043 has 48 divisors (see below), whose sum is σ = 206576112288000. Its totient is φ = 82730169473760.
The previous prime is 131000343212029. The next prime is 131000343212083. The reversal of 131000343212043 is 340212343000131.
It is a happy number.
131000343212043 is a `hidden beast` number, since 1 + 3 + 100 + 0 + 3 + 432 + 120 + 4 + 3 = 666.
It is not a de Polignac number, because 131000343212043 - 216 = 131000343146507 is a prime.
It is a super-2 number, since 2×1310003432120432 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 131000343211998 and 131000343212016.
It is not an unprimeable number, because it can be changed into a prime (131000343212083) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 54556533 + ... + 56907081.
It is an arithmetic number, because the mean of its divisors is an integer number (4303669006000).
Almost surely, 2131000343212043 is an apocalyptic number.
131000343212043 is a deficient number, since it is larger than the sum of its proper divisors (75575769075957).
131000343212043 is a wasteful number, since it uses less digits than its factorization.
131000343212043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2362654 (or 2362642 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 131000343212043 its reverse (340212343000131), we get a palindrome (471212686212174).
The spelling of 131000343212043 in words is "one hundred thirty-one trillion, three hundred forty-three million, two hundred twelve thousand, forty-three".
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