Base | Representation |
---|---|
bin | 11000011001101001… |
… | …01100000000001011 |
3 | 1020210222000222211012 |
4 | 30030310230000023 |
5 | 203312102241303 |
6 | 10003523154135 |
7 | 642426335015 |
oct | 141464540013 |
9 | 36728028735 |
10 | 13100040203 |
11 | 56126a4108 |
12 | 265721594b |
13 | 130a02a8a3 |
14 | 8c3b6b1b5 |
15 | 51a1135d8 |
hex | 30cd2c00b |
13100040203 has 2 divisors, whose sum is σ = 13100040204. Its totient is φ = 13100040202.
The previous prime is 13100040199. The next prime is 13100040229. The reversal of 13100040203 is 30204000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100040203 - 22 = 13100040199 is a prime.
It is a super-2 number, since 2×131000402032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13100040803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550020101 + 6550020102.
It is an arithmetic number, because the mean of its divisors is an integer number (6550020102).
Almost surely, 213100040203 is an apocalyptic number.
13100040203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100040203 is an equidigital number, since it uses as much as digits as its factorization.
13100040203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 13100040203 its reverse (30204000131), we get a palindrome (43304040334).
The spelling of 13100040203 in words is "thirteen billion, one hundred million, forty thousand, two hundred three".
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