131000410433131 has 16 divisors (see below), whose sum is σ = 140831987304960. Its totient is φ = 121462623355680.

The previous prime is 131000410433117. The next prime is 131000410433153. The reversal of 131000410433131 is 131334014000131.

It is a cyclic number.

It is not a de Polignac number, because 131000410433131 - 2³⁵ = 130966050694763 is a prime.

It is a super-2 number, since 2×131000410433131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131000410433096 and 131000410433105.

It is not an unprimeable number, because it can be changed into a prime (131000410433731) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42949641 + ... + 45898501.

It is an arithmetic number, because the mean of its divisors is an integer number (8801999206560).

Almost surely, 2^{131000410433131} is an apocalyptic number.

131000410433131 is a deficient number, since it is larger than the sum of its proper divisors (9831576871829).

131000410433131 is a wasteful number, since it uses less digits than its factorization.

131000410433131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2998674.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131000410433131 its reverse (131334014000131), we get a palindrome (262334424433262).

The spelling of 131000410433131 in words is "one hundred thirty-one trillion, four hundred ten million, four hundred thirty-three thousand, one hundred thirty-one".