Base | Representation |
---|---|
bin | 10011000100000010010… |
… | …110010000001001101001 |
3 | 11122020100110102021220012 |
4 | 103010002112100021221 |
5 | 132430342112204113 |
6 | 2441450244541305 |
7 | 163434062533331 |
oct | 23040226201151 |
9 | 4566313367805 |
10 | 1310004413033 |
11 | 46562a380838 |
12 | 191a799b1835 |
13 | 966c099b474 |
14 | 4759413a0c1 |
15 | 241223a5aa8 |
hex | 13102590269 |
1310004413033 has 2 divisors, whose sum is σ = 1310004413034. Its totient is φ = 1310004413032.
The previous prime is 1310004412949. The next prime is 1310004413059. The reversal of 1310004413033 is 3303144000131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 991713239104 + 318291173929 = 995848^2 + 564173^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310004413033 - 234 = 1292824543849 is a prime.
It is a super-2 number, since 2×13100044130332 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1310004413083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655002206516 + 655002206517.
It is an arithmetic number, because the mean of its divisors is an integer number (655002206517).
Almost surely, 21310004413033 is an apocalyptic number.
It is an amenable number.
1310004413033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310004413033 is an equidigital number, since it uses as much as digits as its factorization.
1310004413033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1310004413033 its reverse (3303144000131), we get a palindrome (4613148413164).
The spelling of 1310004413033 in words is "one trillion, three hundred ten billion, four million, four hundred thirteen thousand, thirty-three".
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