Base | Representation |
---|---|
bin | 1011111010100001100011… |
… | …1101000101000101010011 |
3 | 1201101100120022211020200102 |
4 | 2332220120331011011103 |
5 | 3204112420120330322 |
6 | 43510031044443015 |
7 | 2521306630354661 |
oct | 276503075050523 |
9 | 51340508736612 |
10 | 13100068917587 |
11 | 41a0787427683 |
12 | 1576a6a6a946b |
13 | 74043c847aa2 |
14 | 3340922a5c31 |
15 | 17ab69986792 |
hex | bea18f45153 |
13100068917587 has 2 divisors, whose sum is σ = 13100068917588. Its totient is φ = 13100068917586.
The previous prime is 13100068917491. The next prime is 13100068917601. The reversal of 13100068917587 is 78571986000131.
13100068917587 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13100068917587 is a prime.
It is a super-2 number, since 2×131000689175872 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13100068914587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550034458793 + 6550034458794.
It is an arithmetic number, because the mean of its divisors is an integer number (6550034458794).
Almost surely, 213100068917587 is an apocalyptic number.
13100068917587 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100068917587 is an equidigital number, since it uses as much as digits as its factorization.
13100068917587 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 56.
The spelling of 13100068917587 in words is "thirteen trillion, one hundred billion, sixty-eight million, nine hundred seventeen thousand, five hundred eighty-seven".
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