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13100068917587 is a prime number
BaseRepresentation
bin1011111010100001100011…
…1101000101000101010011
31201101100120022211020200102
42332220120331011011103
53204112420120330322
643510031044443015
72521306630354661
oct276503075050523
951340508736612
1013100068917587
1141a0787427683
121576a6a6a946b
1374043c847aa2
143340922a5c31
1517ab69986792
hexbea18f45153

13100068917587 has 2 divisors, whose sum is σ = 13100068917588. Its totient is φ = 13100068917586.

The previous prime is 13100068917491. The next prime is 13100068917601. The reversal of 13100068917587 is 78571986000131.

13100068917587 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100068917587 is a prime.

It is a super-2 number, since 2×131000689175872 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100068914587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550034458793 + 6550034458794.

It is an arithmetic number, because the mean of its divisors is an integer number (6550034458794).

Almost surely, 213100068917587 is an apocalyptic number.

13100068917587 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100068917587 is an equidigital number, since it uses as much as digits as its factorization.

13100068917587 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 56.

The spelling of 13100068917587 in words is "thirteen trillion, one hundred billion, sixty-eight million, nine hundred seventeen thousand, five hundred eighty-seven".