13100100257 has 2 divisors, whose sum is σ = 13100100258. Its totient is φ = 13100100256.

The previous prime is 13100100149. The next prime is 13100100269. The reversal of 13100100257 is 75200100131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10040240401 + 3059859856 = 100201^2 + 55316^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100100257 is a prime.

It is a super-2 number, since 2×13100100257² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100100557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550050128 + 6550050129.

It is an arithmetic number, because the mean of its divisors is an integer number (6550050129).

Almost surely, 2^13100100257 is an apocalyptic number.

It is an amenable number.

13100100257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100100257 is an equidigital number, since it uses as much as digits as its factorization.

13100100257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 210, while the sum is 20.

Adding to 13100100257 its reverse (75200100131), we get a palindrome (88300200388).

The spelling of 13100100257 in words is "thirteen billion, one hundred million, one hundred thousand, two hundred fifty-seven".