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131001012302 = 265500506151
BaseRepresentation
bin111101000000001000…
…1001101000001001110
3110112010200111221100112
41322000101031001032
54121242224343202
6140103034200022
712315220142366
oct1720021150116
9415120457315
10131001012302
1150614724526
122147bb83012
13c4793a76c4
1464aa3db9a6
15361ab94b52
hex1e8044d04e

131001012302 has 4 divisors (see below), whose sum is σ = 196501518456. Its totient is φ = 65500506150.

The previous prime is 131001012293. The next prime is 131001012313. The reversal of 131001012302 is 203210100131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 203210100131 = 538737722313.

It is a super-2 number, since 2×1310010123022 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750253074 + ... + 32750253077.

It is an arithmetic number, because the mean of its divisors is an integer number (49125379614).

Almost surely, 2131001012302 is an apocalyptic number.

131001012302 is a deficient number, since it is larger than the sum of its proper divisors (65500506154).

131001012302 is an equidigital number, since it uses as much as digits as its factorization.

131001012302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65500506153.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 131001012302 its reverse (203210100131), we get a palindrome (334211112433).

The spelling of 131001012302 in words is "one hundred thirty-one billion, one million, twelve thousand, three hundred two".

Divisors: 1 2 65500506151 131001012302