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13100110123 is a prime number
BaseRepresentation
bin11000011001101001…
…11101000100101011
31020210222011112201211
430030310331010223
5203312112010443
610003524453551
7642430045612
oct141464750453
936728145654
1013100110123
1156127416a1
12265724a2b7
13130a053669
148c3b88879
1551a12919d
hex30cd3d12b

13100110123 has 2 divisors, whose sum is σ = 13100110124. Its totient is φ = 13100110122.

The previous prime is 13100110061. The next prime is 13100110151. The reversal of 13100110123 is 32101100131.

13100110123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100110123 is a prime.

It is a super-2 number, since 2×131001101232 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100110523) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550055061 + 6550055062.

It is an arithmetic number, because the mean of its divisors is an integer number (6550055062).

Almost surely, 213100110123 is an apocalyptic number.

13100110123 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100110123 is an equidigital number, since it uses as much as digits as its factorization.

13100110123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13100110123 its reverse (32101100131), we get a palindrome (45201210254).

The spelling of 13100110123 in words is "thirteen billion, one hundred million, one hundred ten thousand, one hundred twenty-three".