Base | Representation |
---|---|
bin | 10011000100000010101… |
… | …111110001011110010011 |
3 | 11122020100221000011222022 |
4 | 103010002233301132103 |
5 | 132430400320244443 |
6 | 2441451044202055 |
7 | 163434203436062 |
oct | 23040257613623 |
9 | 4566327004868 |
10 | 1310011103123 |
11 | 465633130138 |
12 | 191a8009932b |
13 | 966c21a15b8 |
14 | 47594d9c1d9 |
15 | 24122c77e68 |
hex | 13102bf1793 |
1310011103123 has 2 divisors, whose sum is σ = 1310011103124. Its totient is φ = 1310011103122.
The previous prime is 1310011103119. The next prime is 1310011103129. The reversal of 1310011103123 is 3213011100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310011103123 - 22 = 1310011103119 is a prime.
It is a super-2 number, since 2×13100111031232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310011103129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655005551561 + 655005551562.
It is an arithmetic number, because the mean of its divisors is an integer number (655005551562).
Almost surely, 21310011103123 is an apocalyptic number.
1310011103123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310011103123 is an equidigital number, since it uses as much as digits as its factorization.
1310011103123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1310011103123 its reverse (3213011100131), we get a palindrome (4523022203254).
The spelling of 1310011103123 in words is "one trillion, three hundred ten billion, eleven million, one hundred three thousand, one hundred twenty-three".
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