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131001112034322 = 2321833518672387
BaseRepresentation
bin11101110010010100010010…
…101111110111110000010010
3122011211120202201220220120020
4131302110102233313300102
5114132310234140044242
61142341025143124310
736410342451455205
oct3562242257676022
9564746681826506
10131001112034322
1138817294607a52
1212838a87443696
1358134760561aa
14244c6b819793c
15102298d7716ec
hex772512bf7c12

131001112034322 has 8 divisors (see below), whose sum is σ = 262002224068656. Its totient is φ = 43667037344772.

The previous prime is 131001112034321. The next prime is 131001112034323. The reversal of 131001112034322 is 223430211100131.

It is an interprime number because it is at equal distance from previous prime (131001112034321) and next prime (131001112034323).

It is a sphenic number, since it is the product of 3 distinct primes.

131001112034322 is an admirable number.

It is a super-2 number, since 2×1310011120343222 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001112034292 and 131001112034301.

It is not an unprimeable number, because it can be changed into a prime (131001112034321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10916759336188 + ... + 10916759336199.

It is an arithmetic number, because the mean of its divisors is an integer number (32750278008582).

Almost surely, 2131001112034322 is an apocalyptic number.

131001112034322 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001112034322 is a wasteful number, since it uses less digits than its factorization.

131001112034322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21833518672392.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 131001112034322 its reverse (223430211100131), we get a palindrome (354431323134453).

The spelling of 131001112034322 in words is "one hundred thirty-one trillion, one billion, one hundred twelve million, thirty-four thousand, three hundred twenty-two".

Divisors: 1 2 3 6 21833518672387 43667037344774 65500556017161 131001112034322