Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1100110001010101010 |
3 | 110112010200201011122111 |
4 | 1322000101212022222 |
5 | 4121242241142211 |
6 | 140103040312534 |
7 | 12315221051605 |
oct | 1720021461252 |
9 | 415120634574 |
10 | 131001115306 |
11 | 50614794956 |
12 | 2148001274a |
13 | c479412559 |
14 | 64aa42733c |
15 | 361abb5421 |
hex | 1e804662aa |
131001115306 has 4 divisors (see below), whose sum is σ = 196501672962. Its totient is φ = 65500557652.
The previous prime is 131001115291. The next prime is 131001115327. The reversal of 131001115306 is 603511100131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 110094558025 + 20906557281 = 331805^2 + 144591^2 .
It is a super-2 number, since 2×1310011153062 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750278825 + ... + 32750278828.
Almost surely, 2131001115306 is an apocalyptic number.
131001115306 is a deficient number, since it is larger than the sum of its proper divisors (65500557656).
131001115306 is an equidigital number, since it uses as much as digits as its factorization.
131001115306 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65500557655.
The product of its (nonzero) digits is 270, while the sum is 22.
Adding to 131001115306 its reverse (603511100131), we get a palindrome (734512215437).
The spelling of 131001115306 in words is "one hundred thirty-one billion, one million, one hundred fifteen thousand, three hundred six".
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