Base | Representation |
---|---|
bin | 111101000000001000… |
… | …1100110001010011011 |
3 | 110112010200201011121221 |
4 | 1322000101212022123 |
5 | 4121242241142131 |
6 | 140103040312511 |
7 | 12315221051554 |
oct | 1720021461233 |
9 | 415120634557 |
10 | 131001115291 |
11 | 50614794942 |
12 | 21480012737 |
13 | c479412547 |
14 | 64aa42732b |
15 | 361abb5411 |
hex | 1e8046629b |
131001115291 has 2 divisors, whose sum is σ = 131001115292. Its totient is φ = 131001115290.
The previous prime is 131001115283. The next prime is 131001115327. The reversal of 131001115291 is 192511100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131001115291 - 23 = 131001115283 is a prime.
It is a super-2 number, since 2×1310011152912 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131001115891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500557645 + 65500557646.
It is an arithmetic number, because the mean of its divisors is an integer number (65500557646).
Almost surely, 2131001115291 is an apocalyptic number.
131001115291 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001115291 is an equidigital number, since it uses as much as digits as its factorization.
131001115291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 25.
The spelling of 131001115291 in words is "one hundred thirty-one billion, one million, one hundred fifteen thousand, two hundred ninety-one".
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