Search a number
-
+
131001132022 = 2431523268977
BaseRepresentation
bin111101000000001000…
…1101010001111110110
3110112010200202000120121
41322000101222033312
54121242242211042
6140103040522154
712315221151415
oct1720021521766
9415120660517
10131001132022
11506147a6472
122148002035a
13c47941a047
1464aa42d47c
15361abba367
hex1e8046a3f6

131001132022 has 8 divisors (see below), whose sum is σ = 201071505096. Its totient is φ = 63977296992.

The previous prime is 131001132019. The next prime is 131001132029. The reversal of 131001132022 is 220231100131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1310011320222 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001131987 and 131001132005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131001132029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 761634403 + ... + 761634574.

It is an arithmetic number, because the mean of its divisors is an integer number (25133938137).

Almost surely, 2131001132022 is an apocalyptic number.

131001132022 is a deficient number, since it is larger than the sum of its proper divisors (70070373074).

131001132022 is a wasteful number, since it uses less digits than its factorization.

131001132022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1523269022.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 131001132022 its reverse (220231100131), we get a palindrome (351232232153).

The spelling of 131001132022 in words is "one hundred thirty-one billion, one million, one hundred thirty-two thousand, twenty-two".

Divisors: 1 2 43 86 1523268977 3046537954 65500566011 131001132022