1310012130403 has 2 divisors, whose sum is σ = 1310012130404. Its totient is φ = 1310012130402.

The previous prime is 1310012130391. The next prime is 1310012130491. The reversal of 1310012130403 is 3040312100131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310012130403 - 2²¹ = 1310010033251 is a prime.

It is a super-2 number, since 2×1310012130403² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310012130103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006065201 + 655006065202.

It is an arithmetic number, because the mean of its divisors is an integer number (655006065202).

Almost surely, 2^{1310012130403} is an apocalyptic number.

1310012130403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310012130403 is an equidigital number, since it uses as much as digits as its factorization.

1310012130403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1310012130403 its reverse (3040312100131), we get a palindrome (4350324230534).

The spelling of 1310012130403 in words is "one trillion, three hundred ten billion, twelve million, one hundred thirty thousand, four hundred three".