Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …1100001100101000101011 |
3 | 1201101100201002222201001212 |
4 | 2332220130030030220223 |
5 | 3204113023020243311 |
6 | 43510040304303335 |
7 | 2521311160020461 |
oct | 276503414145053 |
9 | 51340632881055 |
10 | 13100123212331 |
11 | 41a0805041071 |
12 | 1576a84911b4b |
13 | 74044ab77c5c |
14 | 33409959a831 |
15 | 17ab6e60dc8b |
hex | bea1c30ca2b |
13100123212331 has 2 divisors, whose sum is σ = 13100123212332. Its totient is φ = 13100123212330.
The previous prime is 13100123212277. The next prime is 13100123212427. The reversal of 13100123212331 is 13321232100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100123212331 - 222 = 13100119018027 is a prime.
It is a super-2 number, since 2×131001232123312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100123212297 and 13100123212306.
It is not a weakly prime, because it can be changed into another prime (13100123212031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550061606165 + 6550061606166.
It is an arithmetic number, because the mean of its divisors is an integer number (6550061606166).
Almost surely, 213100123212331 is an apocalyptic number.
13100123212331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100123212331 is an equidigital number, since it uses as much as digits as its factorization.
13100123212331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13100123212331 its reverse (13321232100131), we get a palindrome (26421355312462).
The spelling of 13100123212331 in words is "thirteen trillion, one hundred billion, one hundred twenty-three million, two hundred twelve thousand, three hundred thirty-one".
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