Base | Representation |
---|---|
bin | 10011000100000010110… |
… | …100011101101110111011 |
3 | 11122020101000022200000211 |
4 | 103010002310131232323 |
5 | 132430401124123422 |
6 | 2441451130411551 |
7 | 163434220050511 |
oct | 23040264355673 |
9 | 4566330280024 |
10 | 1310012332987 |
11 | 4656338a0156 |
12 | 191a80590bb7 |
13 | 966c2512327 |
14 | 475951dc4b1 |
15 | 24122e1c577 |
hex | 13102d1dbbb |
1310012332987 has 2 divisors, whose sum is σ = 1310012332988. Its totient is φ = 1310012332986.
The previous prime is 1310012332961. The next prime is 1310012333029. The reversal of 1310012332987 is 7892332100131.
It is a weak prime.
It is an emirp because it is prime and its reverse (7892332100131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310012332987 is a prime.
It is a super-2 number, since 2×13100123329872 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310012332927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006166493 + 655006166494.
It is an arithmetic number, because the mean of its divisors is an integer number (655006166494).
Almost surely, 21310012332987 is an apocalyptic number.
1310012332987 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310012332987 is an equidigital number, since it uses as much as digits as its factorization.
1310012332987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 1310012332987 in words is "one trillion, three hundred ten billion, twelve million, three hundred thirty-two thousand, nine hundred eighty-seven".
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