131001243555 has 64 divisors (see below), whose sum is σ = 259000132608. Its totient is φ = 55059264000.

The previous prime is 131001243533. The next prime is 131001243563. The reversal of 131001243555 is 555342100131.

It is not a de Polignac number, because 131001243555 - 2⁷ = 131001243427 is a prime.

It is a super-2 number, since 2×131001243555² (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 151437 + ... + 533793.

It is an arithmetic number, because the mean of its divisors is an integer number (4046877072).

Almost surely, 2^131001243555 is an apocalyptic number.

131001243555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131001243555 is a deficient number, since it is larger than the sum of its proper divisors (127998889053).

131001243555 is a wasteful number, since it uses less digits than its factorization.

131001243555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 382636.

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 131001243555 its reverse (555342100131), we get a palindrome (686343343686).

The spelling of 131001243555 in words is "one hundred thirty-one billion, one million, two hundred forty-three thousand, five hundred fifty-five".