Base | Representation |
---|---|
bin | 111101000000001001… |
… | …0010110101011011011 |
3 | 110112010201002021012221 |
4 | 1322000102112223123 |
5 | 4121242314022021 |
6 | 140103044444511 |
7 | 12315222540121 |
oct | 1720022265333 |
9 | 415121067187 |
10 | 131001314011 |
11 | 50614910177 |
12 | 214800a9737 |
13 | c479481b29 |
14 | 64aa479911 |
15 | 361ac04241 |
hex | 1e80496adb |
131001314011 has 2 divisors, whose sum is σ = 131001314012. Its totient is φ = 131001314010.
The previous prime is 131001313991. The next prime is 131001314023. The reversal of 131001314011 is 110413100131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131001314011 - 229 = 130464443099 is a prime.
It is a super-2 number, since 2×1310013140112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131001314051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500657005 + 65500657006.
It is an arithmetic number, because the mean of its divisors is an integer number (65500657006).
Almost surely, 2131001314011 is an apocalyptic number.
131001314011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001314011 is an equidigital number, since it uses as much as digits as its factorization.
131001314011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 131001314011 its reverse (110413100131), we get a palindrome (241414414142).
The spelling of 131001314011 in words is "one hundred thirty-one billion, one million, three hundred fourteen thousand, eleven".
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